Proposal: 1) Number (integer or decimal) to Array 2) Array to Number (integer or decimal)

Naveen Chawla naveen.chwl at gmail.com
Thu Mar 7 21:56:34 UTC 2019


What is the real world use case, presuming it's not just an academic
exercise

On Thu, 7 Mar 2019, 9:08 pm guest271314, <guest271314 at gmail.com> wrote:

> Ability to adjust *nth* digit of an integer or decimal by adjusting
> decimal or integer at *nth* index of array, to try to solve OEIS A217626
> oeis.org/A217626 directly, for example
>     ~~(128.625*9*1.074)//1243
>     ~~(128.625*9*1.144)//1324
> where the decimal portion can be manipulated by referencing the index of
> an array, then converting the array back to a number.
>
> On Thu, Mar 7, 2019 at 8:55 PM Jeremy Martin <jmar777 at gmail.com> wrote:
>
>> Can you explain the motivation for this proposal?
>>
>> At first blush, this seems like an incredibly arbitrary pair of value
>> conversion utilities. Are there real world applications for this?
>>
>> On Thu, Mar 7, 2019 at 3:43 PM guest271314 <guest271314 at gmail.com> wrote:
>>
>>>
>>>
>>> ---------- Forwarded message ---------
>>> From: guest271314 <guest271314 at gmail.com>
>>> Date: Thu, Mar 7, 2019 at 8:35 PM
>>> Subject: Proposal: 1) Number (integer or decimal) to Array 2) Array to
>>> Number (integer or decimal)
>>> To: <es-discuss at mozilla.org>
>>>
>>>
>>> Original concept: Integer or decimal to array and array to decimal or
>>> integer https://codegolf.meta.stackexchange.com/a/17223
>>>
>>> Proof of concept (with bugs)
>>>
>>> function numberToArray(n) {
>>>
>>>   if (Math.abs(n) == 0 || Math.abs(n) == -0) {
>>>     return [n]
>>>   }
>>>
>>>   const r = [];
>>>
>>>   let [
>>>     a, int = Number.isInteger(a), d = g = [], e = i = 0
>>>   ] = [ n || this.valueOf()];
>>>
>>>   if (!int) {
>>>     let e = ~~a;
>>>     d = a - e;
>>>     do {
>>>       if (d < 1) ++i;
>>>       d *= 10;
>>>     } while (!Number.isInteger(d));
>>>   }
>>>
>>>   for (; ~~a; r.unshift(~~(a % 10)), a /= 10);
>>>
>>>   if (!int) {
>>>     for (; ~~d; g.unshift(~~(d % 10)), d /= 10);
>>>     g[0] = g[0] * (1 * (10 ** -i))
>>>     r.push(...g);
>>>   }
>>>
>>>   return r;
>>> }
>>> function arrayToNumber(a) {
>>>   if ((Math.abs(a[0]) == 0 || Math.abs(a[0]) == -0)
>>>      && a.length == 1)
>>>
>>>
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