an operator for ignoring any exceptions

[kai zhu]

-1
in my real-world experience, JSON.parse and nodejs fs.readFileSync are the
only 2 common use-cases that would benefit from this.  its more practical
to use helper-functions for those 2 use-cases rather than change the
javascript language yet again (besides, returning an empty string is
commonly more useful for me than returning undefined for failed
fs.readFileSync).

this is also a likely footgun that would get abused by novice programmers
for many inappropriate use-cases.
On Aug 2, 2017 11:59 AM, "Sheng TIAN" <llltgd at gmail.com> wrote:

> Is there any proposal for an one unary operator for ignoring any
> exceptions.
>
> (I have not search out any related threads. But it is useful IMO, so I'm
> wondering if this had been discussed.)
>
> For example, we may introduce an unary operator called `try` which
>
> 1. calculate the operand first
> 2. if it not throw, return as is
> 3. otherwise return undefined
>
> This operator may be used when exceptions should always be ignored.
>
> Example:
>
>     let resp;
>     try {
>       resp = JSON.parse(xhr.responseText);
>     } catch (_ignore) { /* do nothing here */ }
>
> may be simplified to:
>
>     const resp = try JSON.parse(xhr.responseText);
>
> Another Example:
>
>     var age = user && user.age;
>
> to:
>
>     var age = try user.age;
>
> (Note, in such case, if operand is start with curly braces "{", it must
> be wrapped in parentheses "()".)
>
> _______________________________________________
> es-discuss mailing list
> es-discuss at mozilla.org
> https://mail.mozilla.org/listinfo/es-discuss
>
>
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://mail.mozilla.org/pipermail/es-discuss/attachments/20170802/c9fdb80d/attachment.html>