The `super` keyword doesn't work as it should?

Allen Wirfs-Brock allen at
Tue Jul 19 23:20:01 UTC 2016

> On Jul 19, 2016, at 11:45 AM, Raul-Sebastian Mihăilă <raul.mihaila at> wrote:
> An alternative would be to consider the object where the method key was found as the home object of the method.

that was considered while designing ES6.  The problem is that it introduces an additional implicit parameter (or equivalent overhead) for every method call, regardless of whether or not it is actually needed by the  invoked method.


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