Consider javascript already support for default parameters, so maybe we can use the default parameter to specify the strong type.

Mon May 18 18:22:47 UTC 2015

What if I have an "int64" function already defined? Will this skip over my
int64 function? What about `a = something(0)` - will that call my
"something" function, whereas "int64" is special and skipped over?

On Mon, May 18, 2015 at 11:16 AM, Benjamin Gruenaum <benjamingr at gmail.com>
wrote:

> What about non-default parameters?
>
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