'stream' values

[Erik Arvidsson]

entries() returns an iterator.

To sort you need to convert to an array first.

let a = [...map.entries()];
a.sort()

On Wed, May 6, 2015, 08:37  <Mohan.Radhakrishnan at cognizant.com> wrote:

>  That line matches my Java code almost exactly. My traceur transpiler
> though throws ‘TypeError: map.entries(...).sort is not a function’. Should
> I switch the traspiler ?
>
>
>
> Thanks,
>
> Mohan
>
>
>
> *From:* Mark Volkmann [mailto:r.mark.volkmann at gmail.com]
> *Sent:* Wednesday, May 06, 2015 4:19 PM
> *To:* Radhakrishnan, Mohan (Cognizant)
> *Cc:* <es-discuss at mozilla.org>
> *Subject:* Re: 'stream' values
>
>
>
> The entries method of a Map doesn't take a function. It does return an
> array though. That array contains [key, value] arrays. So you could do this.
>
>
>
>   map.entries().sort(([k1, v1], [k2, v2]) =>
> k1.localeCompare(k2)).forEach(([k, v]) => do-something);
>
>
> ---
>
> R. Mark Volkmann
>
> Object Computing, Inc.
>
>
> On May 6, 2015, at 4:27 AM, <Mohan.Radhakrishnan at cognizant.com> <
> Mohan.Radhakrishnan at cognizant.com> wrote:
>
>  Hi,
>
>        Can I stream values and operate on them like this ? I have a map
> and I would like to stream them. I also want to chain the functions. So,
> for example, I may sort the map’s values and pass them on.
>
>
>
> map.entries((e,m) => sort by using a predicate ).foreach(manipulate the
> map’s values);
>
>
>
> Thanks,
>
> Mohan
>
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