Exponentiation operator precedence
Claude Pache
claude.pache at gmail.com
Tue Aug 25 17:54:28 UTC 2015
> Le 25 août 2015 à 19:25, Mark S. Miller <erights at google.com> a écrit :
>
> It also does not work. x ** y ** z, if we allow it at all, must be right associative. It must parse as x ** (y ** z).
>
Unless I missed something, it *is* right-associative.
—Claude
>
> On Tue, Aug 25, 2015 at 10:08 AM, Mark S. Miller <erights at google.com <mailto:erights at google.com>> wrote:
> It does not work as well as simply omitting ** entirely.
>
>
> On Tue, Aug 25, 2015 at 9:42 AM, Isiah Meadows <isiahmeadows at gmail.com <mailto:isiahmeadows at gmail.com>> wrote:
> I like this. It works very well.
>
> On Tue, Aug 25, 2015, 12:38 Claude Pache <claude.pache at gmail.com <mailto:claude.pache at gmail.com>> wrote:
>
> I think the following grammar could work.
> Replace the current (ES2015) PostfixExpression production with:
>
> ```
> IncrementExpression:
> LeftHandSideExpression
> LeftHandSideExpression [no LineTerminator here] ++
> LeftHandSideExpression [no LineTerminator here] --
> ++ LeftHandSideExpression
> -- LeftHandSideExpression
> ```
>
> And define UnaryExpression as:
>
> ```
> UnaryExpression:
> IncrementExpression
> delete UnaryExpression
> void UnaryExpression
> typeof UnaryExpression
> ++ UnaryExpression
> + UnaryExpression
> -- UnaryExpression
> - UnaryExpression
> ~ UnaryExpression
> ! UnaryExpression
> IncrementExpression ** UnaryExpression
> ```
>
> where the following production (which exists only to avoid to confusingly interpret, e.g., `++x++` as `+ +x++`):
>
> ```
> UnaryExpression:
> ++ UnaryExpression
> -- UnaryExpression
> ```
>
> yields a static SyntaxError (or a static ReferenceError if we want to be 100% compatible ES2015).
>
>
> That way, we have the following expected behaviour:
> * in/decrement operators bind most tightly;
> * unary and exponentiation operators are applied from right to left.
>
>
> —Claude
>
>
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>
>
>
> --
> Cheers,
> --MarkM
>
>
>
> --
> Cheers,
> --MarkM
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