Syntax sugar for partial application
liorean
liorean at gmail.com
Thu Apr 9 13:04:08 UTC 2015
Do we really need it?
Your «foo(1, ?, 2);» is equivalent to «a=>foo(1,a,2)».
Your «foo(?, 1, ???);» is equivalent to «(a,...b)=>foo(a,1,...b)».
Your «foo(1, ???, 2);» is equivalent to «(...a)=>foo(...[1,...a,2])».
Also, the ? token is already taken by the ternary conditional
operator. Do we really want to overload it here for a nullary
operator/special form, when we have as low overhead syntax as we
already do in fat arrows for doing the exact same thing?
--
David "liorean" Andersson
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