for-of loops, IteratorClose and the rest of the iterations in the spec

[André Bargull]

> >>>/  Seems to me like it's just a matter of wrapping the relevant bits (which ones, though?
> />>/  whatever constitutes the loop "body"
> />/  
> />/  OK.  That's fairly straightforward.
> />/  
> />>/  You also will need a finally clause, if the loop body contains any explicit returns.
> />/  
> />/  It only does when the iterator claims there are no more things to be had, in which case do I still want to be calling the return() thing?
> /
> No, you only call 'return' when exiting the loop before the iterator has indicated that it is 'done'..
>

Just for the sake of completeness, here is complete translation of 
`for-of` to ES5 syntax.

ES6 for-of statement:
---
for (var value of iterable) {
   if (doReturn) return;
   if (doBreak) break;
   if (doContinue) continue;
   otherExpression;
}
---

Translated to ES5 syntax:
---
var $iterable = iterable;
if ($iterable === undefined || $iterable === null) {
   throw new TypeError();
}
var $iterator = Object($iterable)[Symbol.iterator]();
if (Object($iterator) !== $iterator) {
   throw new TypeError();
}
while (true) {
   var $nextResult = $iterator.next();
   if (Object($nextResult) !== $nextResult) {
     throw new TypeError();
   }
   if ($nextResult.done) {
     break;
   }
   var $nextValue = $nextResult.value;
   var $callClose = false;
   try {
     value = $nextValue;
     if (doReturn) { $callClose = true; return; }
     if (doBreak) { $callClose = true; break; }
     if (doContinue) continue;
     otherExpression;
   } catch ($exception) {
     try {
       if ("return" in $iterator) {
         $iterator.return();
       }
     } catch ($ignore) {
       // ignore
     }
     throw $exception;
   } finally {
     if ($callClose) {
       if ("return" in $iterator) {
         $iterator.return();
       }
     }
   }
}
---

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