RegExp spec question

Andrea Giammarchi andrea.giammarchi at gmail.com
Wed Jul 16 00:31:38 PDT 2014


expected by specs ... try this

r = /\u0020+$/g; p = r.exec("  "); r.lastIndex = 0; q = r.exec("  ");
alert(JSON.stringify([p, q]))

and you are good to go

... without resetting lastIndex, you can also use "  ".replace(r,
'whatever') and it's going to work every time.

Have a look at these slides to know more about JS RegExp

https://github.com/WebReflection/talks/tree/master/BerlinJS



On Wed, Jul 16, 2014 at 12:26 AM, Alex Vincent <ajvincent at gmail.com> wrote:

> r = /\u0020+$/g; p = r.exec("  "); q = r.exec("  "); JSON.stringify([p, q])
> // "[[\"  \"],null]"
>
> Why does calling exec the second time generate null?  When I try the
> regular expression without the /g flag, I get:
> // "[[\"  \"],[\"  \"]]"
>
>
>
> --
> "The first step in confirming there is a bug in someone else's work is
> confirming there are no bugs in your own."
> -- Alexander J. Vincent, June 30, 2001
>
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