detecting JS language mode for tools
oliver at apple.com
Fri Jan 24 09:17:08 PST 2014
I believe the conclusion with |let| was to identify let syntax:
let foo(=*) is syntactically unambiguous, just a bit more work to identify.
yield is only valid in generators (function*) so that gets reserved the moment you enter a generator definition
On Jan 24, 2014, at 9:11 AM, John Lenz <concavelenz at gmail.com> wrote:
> You don't get "let", "function" block scoping, "yield" or other incompatible constructs. (let and yield aren't a reserved word in ES5 "loose)
> On Fri, Jan 24, 2014 at 8:49 AM, Tab Atkins Jr. <jackalmage at gmail.com> wrote:
> On Fri, Jan 24, 2014 at 8:48 AM, John Lenz <concavelenz at gmail.com> wrote:
> > For static language parsers there seems to be a bit of a dilemma with ES6
> > modules. I would appreciate a correct or hint.
> > Here is my understanding:
> > - standard scripts as we know them today will parse in the browser as
> > "loose" code
> > - scripts with the standard "use strict" will parse as "strict" with
> > access to all ES6 goodness
> Loose code will also get all the ES6 goodness. 1JS and all that.
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