Elegant way to generate string from tagged template?

Brendan Eich brendan at mozilla.org
Tue Dec 23 15:39:09 PST 2014


Perhaps the most elegant way is functional composition on arrays, not 
string hacking just-so imperative coding: zip composed with flatten and 
join. You could even use underscore.js:

http://underscorejs.org/#flatten
http://underscorejs.org/#zip

but JS's OO standard library style prefers method chaining. Array lacks 
standard zip and flatten, although concat does one level of flattening:

js> Array.prototype.flatten1 = function () { return [].concat.apply([], 
this); };
(function () { return [].concat.apply([], this); })
js> Array.prototype.zip = function (b) { var r = []; var n = 
Math.min(this.length, b.length) ; for (var i = 0; i < n; i++) 
r.push([this[i], b[i]]); return r; }
(function (b) { var r = []; var n = Math.min(this.length, b.length) ; 
for (var i = 0; i < n; i++) r.push([this[i], b[i]]); return r; })
js> ['a', 'b', 'c'].zip([1, 2, 3]).flatten1().join('');
"a1b2c3"

This is just a quick sketch. A real standard library zip would be a bit 
more involved, ditto any flatten or flatten1 ;-).

/be


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