Generator issue: exceptions while initializing arguments

[Tobie Langel]

On Sep 10, 2012, at 9:48 PM, Jason Orendorff <jason.orendorff at gmail.com> wrote:

> On Mon, Sep 10, 2012 at 12:50 PM, Kevin Smith <khs4473 at gmail.com> wrote:
>>>>    function f(x=EXPR1, y=EXPR2) { BODY }
>>>>    ===>
>>>>    function f(x, y) {
>>>>        if (x === void 0) x = EXPR1;
>>>>        if (y === void 0) y = EXPR2;
>>>>        BODY
>>>>    }
>>
>> I'm not so sure - the desugaring above would mean that default expressions
>> would have visibility across curly-brace boundaries, which I find to be
>> quite surprising.
>
> It is surprising.  It could even bite unwary programmers.  But in what
> scope do you propose to evaluate default-param expressions?

In their lexical scope.

--tobie