shortcut for private(this)

Erik Arvidsson erik.arvidsson at
Fri Jan 20 10:59:50 PST 2012

On Fri, Jan 20, 2012 at 10:46, Herby Vojčík <herby at> wrote:
> No, I asked for something else. How do it do: "get a private property of
> <<foo>> whose name is computed by <<expression>>"? Something like
> foo.@[expr]? Or is there no way to do it?
> In other words, what is [] syntax for foo. at bar? foo.@["bar"]? foo["@bar"]?

@bar is a shorthand[*] for this[bar]
object. at bar is a shorthand[*] for object[bar]

There is no way to compute a string "bar" to do the lookup since that
would break private name encapsulation:

let object = ...
  let key = Name.create()
  let secret = {}
  object. at key = secret

There must be no way to get access to secret here.

[*] Using @ does not really invoke []. That is important if private
names are going to work with the extended collection proposals Allen


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