Using function.prototype.bind without breaking function.prototype.apply

[Mark S. Miller]

On Wed, Sep 7, 2011 at 2:52 PM, Mark S. Miller <erights at google.com> wrote:

>
>
> If there is not I propose using `undefined` to tell Function.prototype.bind
>> to leave thisArg flexible.
>>
>
> We cannot use 'undefined' for this, as we already use f.bind(undefined) in
> order to ensure that f's "this" is useless, and therefore harmless.
>

Of course, that only works if f is constrained to be strict, which we ensure
by other means.

-- 
    Cheers,
    --MarkM
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