The class operator: a bridge between object and function exemplers
Brendan Eich
brendan at mozilla.com
Mon Nov 14 18:56:10 PST 2011
On Nov 14, 2011, at 6:47 PM, Axel Rauschmayer wrote:
>>> Is a dual role even necessary? Why not stick to just class declaration? Looking through the eyes of an outsider, class { ... } looks like a class declaration. Given that we already have typeof and instanceof, wouldn’t an outsider expect a name such as classof? Furthermore, if object exemplars and function exemplars are to exist in parallel. Then:
>>>
>>> function Foo() {};
>>> var f = new Foo();
>>> classof f === Foo // true
>>>
>>> let Foo = {};
>>> var f = new Foo();
>>
>> This could succeed, due to 'constructor' inherited from Object.prototype. But, it could fail if we require an own constructor, or at least an inherited one whose value is a function object (or callable object if host) whose .prototpye is the exemplar.
>>
>>> classof f === Foo // true
>>
>> If new Foo() throws, you won't reach here, and all is consistent.
>
>
> Sorry, mucked it up (shouldn’t email when tired):
>
> let Foo = { constructor: function() {} }; // or any valid object exemplar on the RHS, really
> var f = new Foo();
> classof f === Foo // true
In that case class f === f.constructor && f.constructor === Foo per Allen's last post about this wiring.
/be
>
> --
> Dr. Axel Rauschmayer
> axel at rauschma.de
>
> home: rauschma.de
> twitter: twitter.com/rauschma
> blog: 2ality.com
>
>
>
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