The class operator: a bridge between object and function exemplers
Axel Rauschmayer
axel at rauschma.de
Mon Nov 14 18:36:03 PST 2011
> Given this meaning of "class" when testing a value, I'm not sure if we can rescue the pun above by which we use the same operator to define a class. If forced to choose only one of these two roles for the "class" keyword, I'd prefer to use it only to define a class, not to test values. But having only just noticed this discrepancy, I am also not sure we cannot rescue the pun. Let's try.
Is a dual role even necessary? Why not stick to just class declaration? Looking through the eyes of an outsider, class { ... } looks like a class declaration. Given that we already have typeof and instanceof, wouldn’t an outsider expect a name such as classof? Furthermore, if object exemplars and function exemplars are to exist in parallel. Then:
function Foo() {};
var f = new Foo();
classof f === Foo // true
let Foo = {};
var f = new Foo();
classof f === Foo // true
The above would not hold for `class`.
--
Dr. Axel Rauschmayer
axel at rauschma.de
home: rauschma.de
twitter: twitter.com/rauschma
blog: 2ality.com
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