Making "super" work outside a literal?

Brendan Eich brendan at
Thu Jun 23 11:00:13 PDT 2011

On Jun 23, 2011, at 7:43 AM, Sean Eagan wrote:

> Actually, it's simpler than this.  One can never obtain a reference to
> a super delegate function, only call it as a method or accessor getter
> or setter.

JS has first-class functions. We are not going to make invoke-only methods. You're way up that wrong tree.


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