Making "super" work outside a literal?

Juan Ignacio Dopazo dopazo.juan at gmail.com
Wed Jun 22 10:07:26 PDT 2011


On Wed, Jun 22, 2011 at 1:01 PM, Sean Eagan <seaneagan1 at gmail.com> wrote:

> Its value is already resolved via prototype climbing,  I don't see the
> tremendous cost is simply making this value accessible within the
> function activation which occurs as a result of the prototype
> climbing.


Can the value of a dynamic super be unambiguously resolved with prototype
climbing and without an extra implicit parameter?

Juan
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