Operators ||= and &&=
brendan at mozilla.com
Wed May 6 14:38:26 PDT 2009
On May 6, 2009, at 1:43 PM, Ash Berlin wrote:
>> I don't think ||= and ??= are very difficult to define clearly.
>> Perhaps just a line each in terms of the expanded syntax. I don't
>> think they would add much bloat to engines. Perhaps just better to
>> them both and move on to discussing classes, lambdas, or processes.
> a ||= b;
> a = a || b;
Is the reference to |a| computed only once, and before b is evaluated?
This matters in JS since evaluating b could change where |a| exists on
the scope chain.
> a ??= b;
> a = a === undefined ? b : a;
In no case should |a| be evaluated twice here, but this desugaring
Nothing's ever as simple as you want :-P.
> You could make a case for adding a ?? operator for symmetry. Example
> of usage:
> some_func(a, b ?? "c" );
Roger that, given ??= it would be strange to leave out ??.
I'm still trying to leave out both ;-).
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