extracting namespace from a property

Yuh-Ruey Chen maian330 at gmail.com
Mon Feb 5 19:05:08 PST 2007

Brendan Eich wrote:
>    intrinsic static function invoke(ns : Namespace, id : string) : Name
>      new Name(ns, id);

invoke is called when Name is called as a function, right? I've seen
this used before in Enumerator - just want to make sure.

> An enumerating for-in loop or comprehension must reflect an  
> enumerable property name as a Name instance if the property was  
> defined with an explicit or default namespace other than public.  
> Otherwise, with no or a public namespace, enumerating for-in reflects  
> the name as a string per ES1-3 and existing JS implementations.

Although this helps, it would still be a hassle to have to check whether
an enumerated property n is a Name or String. I can't do n.identifier if
n is a String.

How about this: Each enumerated property n is always an instance of
Name. If n doesn't have a qualifier, n.qualifier would be null, while
n.identifier would be n's id. Thus, to get a property's id, n.identifier
would work regardless of whether n has a qualifier. typeof(Name) would
be "string". Name's prototype would be a String, so name instanceof
String is true. These two requirements should be enough to satisfy ES3

> The only detailing that remains is what Name.prototype.toString  
> should do. Current thinking is something like "[namespace public  
> n]::m" for the example in the Problem Statement. Comments welcome.
> /be

First, if n.qualifier is null or undefined, toString() should just
return n.identifier. Second, it doesn't really matter to me how
n.qualifier would be represented in toString().


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